Based on your knowledge of gas laws, how do you now two variables are inversely
ID: 517716 • Letter: B
Question
Based on your knowledge of gas laws, how do you now two variables are inversely proportional to each other? Give an example of two variables that are inverse to each other and two variables that vary directly in proportion to each other. Please give specific examples for such variables. The reading on a Kelvin scale is 323K. On the Celsius scale the reading would be what? A student did an experiment to calculate percent composition of a mixture of Potassium chlorate and Potassium chloride. At the end of the experiment, student determined that the mixture had 71 percent of m chlorate and 39 percent of potassium chloride. Do you think this data make sense? Explain your reasoning A chemist heated an unknown hydrate, MgSO_4 X H_2O, in a crucible. The water was driven off, leaving the anhydrous salt in the crucible. After cooling, the mass of the anhydrous salt and water lost was calculated. The mass of the hydrated salt was 2.5 grams g and the mass of the water lost was 1.1 gram. Is it possible to find the mass of the anhydrous salt? Please show your calculations or explain What are the three main variables that are involved in Boyle's law. Name them with their correct units. Which one of these three variables that you must convert to its standard unit when solving a problem on gas law.Explanation / Answer
Consider ideal gas law
PV = nRT where R is constant
P is proportional to T
P is proportional to n
where as P is inversely proportinal to V
we know that these are inversely proportional if we keep all other constant as
PV = k where k is constant
P = k/V
now if increase V , p will decrease and if you decrease V, P will decrease
T is inversely proportional to n
Tempertaure = 323 K
Kelvin to celcius we have to subtract 273 K
Celcius temperature = 323 - 273 = 50 C
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