What is the mass of calcium phosphate that can be prepared from 3.08 g of Na3PO4

Question

What is the mass of calcium phosphate that can be prepared from 3.08 g of Na3PO4? Na3PO4(aq)+Ca(OH)2(aq)Ca3(PO4)2(s)+NaOH(aq)
Express your answer with the appropriate units. What is the mass of calcium phosphate that can be prepared from 3.08 g of Na3PO4? Na3PO4(aq)+Ca(OH)2(aq)Ca3(PO4)2(s)+NaOH(aq)
Express your answer with the appropriate units. What is the mass of calcium phosphate that can be prepared from 3.08 g of Na3PO4? Na3PO4(aq)+Ca(OH)2(aq)Ca3(PO4)2(s)+NaOH(aq)
Express your answer with the appropriate units.

Explanation / Answer

Mass of Na3Po4 = 3.08 g

molar mass of Na3Po4 = 163.94 g/mol

No of moles of Na3Po4 = 3.08/ 163.94 = 0.0188 mol

Balances chemical equation

2 Na3PO4(aq)+3 Ca(OH)2(aq)?Ca3(PO4)2(s)+6 NaOH(aq)

Now 2 moles of Na3PO4 reacts to form 1 mole of Ca3(PO4)2

0.0188 moles of Na3PO4 reacts to form = (1 * 0.0188)/2 = 0.0094 mole of Ca3(PO4)2

Molar mass of Ca3(PO4)2 = 310.18 g/mol

thus mass of Ca3(PO4)2 produced = no of moles * molar mass = 0.0094 * 310.18 = 2.916 g

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