Assuming the diameter of the field with low power is 1.4 mm, you should now calc

Question

Assuming the diameter of the field with low power is 1.4 mm, you should now calculate the diameter with medium power, high power, and oil immersion.

An item of information: The size of the field varies inversely to the magnification, ie.., as the magnification increases the size of the field decreases.

1. The 10X objective magnifies 2.5 times as much as the 4X and the size of the field would be 0.4 of the 4X field or ____mm(?)

2. The 40X objective magnifies four times as much as the 10X and the size of the field would be 1/4 of the 10X field or ____mm(?)

3. The 100X objective magnifies ten times as much as the 10X and the size of the field would be 1/10 of the 10X field or ____mm or ____ micrometers

***Please provide explanation as well.

Explanation / Answer

The diameter of given field under low power is = 0.4mm

The field diameter decreases as the magnification increases. The diamter under 4X filed is 1.4 mm, field diameter decreases by 0.4 times with 10x i.e., the filed diameter would be equal to 1.4* 0.4 = 0.56 mm.

1. The 10X objective magnifies 2.5 times as much as the 4X and the size of the field would be 0.4 of the 4X field or ___0.56_mm(?)

2. The 40X objective magnifies four times as much as the 10X and the size of the field would be 1/4 of the 10X field or _0.14___mm. (Since 0.56/4 = 0.14).

3. The 100X objective magnifies ten times as much as the 10X and the size of the field would be 1/10 of the 10X field or _0.056___mm or __56__ micrometers. (Since 0.56/10 = 0.056, 1 mm = 1000 micrometers)

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