Calculate Delta S degree_ for the following reaction. The S degree for each spec

Question

Calculate Delta S degree_ for the following reaction. The S degree for each species is shown below the reaction. All answers are in units of J/mol middot K. C_2H_6(g) rightarrow C_2H_2(g) + 2 H_2(g) S degree (J/mol middot K) 229.2 200.9 130.7 A) +233.1 B) +560.8 C) -102.4 D) +229.2 E) -233.1 For the following example, identify the following. NaCl(s) rightarrow Na^+ (g) + Cl^- (g) A) a negative Delta H and a negative Delta S B) a positive Delta H and a negative Delta S C) a negative Delta H and a positive Delta S D) a positive Delta H and a positive Delta S E) It is not possible to determine without more information. Consider a reaction that has a positive Delta H and a negative Delta S. Which of the following statements is true? A) This reaction will be spontaneous at all temperatures. B) This reaction will be at temperatures. C) This reaction will be spontaneous only at high temperatures. D) This reaction will be spontaneous only at low temperatures. E) It is not possible to determine without more information. Below what temperature the following reaction become nonspontaneous? FeO(s) + CO(g) + Fe(s) Delta H = -11.0 kJ/mol; Delta S = -17.4 J/mol middot K A) 191 K B) 298 K. C) 632 K. D) This reaction is nonspontaneous at all temperatures. E) This reaction is spontaneous at all temperatures. Delta G degree_rxn using the following information. Standard conditions are at 298 K. answer are in units of kJ/mol. 2 H_2S(g) + 3 O_2 (g) rightarrow 2 H_2O(l) + 2 SO_2 (g) Delta H degree = + 1.12 kJ/mol; Delta S degree = -390.7 J/mol middot K + 28.4 B) -348 C) +440 D) -58.3 E) +118 law to calculate Delta G degree_rxn in kJ/mol using the following information. + O_3 (g) rightarrow Cl(g) + 2 O_2 (g) Delta G degree _rxn = ? rightarrow O_3 (g) Delta G degree_rxn = -489.6 kJ/mol + O_3 (g) rightarrow ClO(g) + O_2 (g) Delta G degree_rxn = -34.5 kJ/mol B) -210.3 C) +455.1 D) +262.1 E) -472.4 the equilibrium constant for the following reaction at 298 K.

Explanation / Answer

Q4.

dS = Sproducts - Sreactatns

dS = S-C2H2+ 2*S-H2 - (S-C2H6)

substitute data

dS = (200.9 + 2*130.7) - (229.2)

dS = 233.1 J/K

best answer is A

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