Once you have confirmed that the graph represents either a direct or inverse rel

Question

Once you have confirmed that the graph represents either a direct or inverse relationship, print a copy of the graph, with the graph of pressure vs. volume and its best-fit curve displayed. With the best - fit curve still displayed proceed directly to the Processing the Data section. With the best-fit curve still displayed, choose Interpolate from the Analyze menu. A vertical cursor now appears on the graph. The cursor's volume and pressure coordinates are displayed in the floating box. Move the corresponding pressure value. Now move the cursor until the volume n value is doubled (10.0 mL). What does your data show happens to the pressure when the volume is doubled? Show the pressure values in your answer. Using the same technique as in Question 1, what does your data show happens to the pressure if the volume is halved from 20.0 mL to 10.0 mL? Show the pressure values in your answer. Using the same technique as in Question 1, what does your data show happens to the pressure if the volume is tripled from 5.0 mL to 15.0 mL? Show the pressure values in your answer. From your answers to the first three questions and the shape of the curve the plot of pressure vs, volume, do you think the relationship between the pressure and volume of a confined gas is direct or inverse? Explain your answer. Based on your data, what would you expect the pressure to be if the volume of the syringe was increased to 40.0 mL? Explain or show work support your answer. Based on your data, what would you expect the pressure to be if the volume of the syringe was decreased to 2.5 mL? Explain or show work to support your answer.

Explanation / Answer

a plot of (1/V)*100 vs P is drawn which gives straiight line whose slope is 0.084

or (!/V)*100 = 0.084*P

when volume is 20 ml

100/20 = 0.084*P

P= 5/0.084=59.5 Kpa

when volume is reduced to 10ml, pressure is increased to 2*59.5= 119 Kpa

3. when the volume is 5ml, 100/5= 0.084*P

P= 20/0.084= 238 Kpa

when the volume is tripled, pressure gets reduced to 1/3, pressure becoemes 238/3= 79.333

when V=40ml. 100/40 = P*0.084

P= 29.77Kpa

when V= 2.5ml, 100/2.5= P*0.084

P= 476.2 Kpa

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