According to the equation above, what would be the equilibrium expression? What
ID: 526709 • Letter: A
Question
According to the equation above, what would be the equilibrium expression? What would be the equilibrium constant if [N_2 O_3] = 0.50 M, [NO_2] = 0.100 M, and [O_2] = 0.025 M? Write the equilibrium expression for the following chemical reaction: CaCO_3 (s) Ba CaO (s) + CO_2 (g) According to the following equation, which species is reduced? Oxidized? Which one loses electrons? Gains? Which is the reducing agent? Oxidizing agent? Mg (s) + Pb^2+ a Pb (s) + Mg^2+ What is the oxidation state of each of the atoms in the following equation? CH_4 + O_2 a CO_2 + H_2 O What is the balanced nuclear equation for the alpha decay of U-238? How long would it take for 10 mg of baby aspirin to remain in your system (1 tablet = 81 mg) if the half-life of aspirin is 3 hours?Explanation / Answer
Q23 --> please provide "above" equation
Q24 --> please provide "above" equation
Q25
The K expression:
K = [products]^p / [reactants]^r
K = [CO2][CaO] / [CaCO3]
note that solids hav eactivity of 1 so
K = [CO2]*1/1
then
K = [CO2]
Q26
a= which specie is geting reduced
reduction is gain fo electrons
so
Pb2+ geso from 2+ to 0, this gains 2 electrons, Pb2+ is reducing
b) therefore, the oxidation is the loss of electrons, Mg goes from 0 to +2, then this is oxidized
c)
Mg is the one losing electrons
d)
Pb is the one gaining electrons
e)
Reducing agent is the one that gets oxidized, so Mg(s) is the reducing agent
f)
therefore, the oxidizing agent is the Pb2+
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