Given that E degree red = - 0.40 V for Cd^2+/Cd at 25 degree C, find E degree an

Question

Given that E degree red = - 0.40 V for Cd^2+/Cd at 25 degree C, find E degree and E for the concentration cell using shorthand notation below. Cd(s)|Cd^2+ (1.0 times 10^-5 M) || Cd^2+ (0.100 M) | Cd (s) A) E degree = 0.00 V and E = +0.24 V B) E degree = 0.000 V and E = +0.12 V C) E degree = -0.40 V and E = -0.16 V D) E degree = -0.40 V and E = -028 V Describe the reactions during the electrolysis of water. A) Oxygen is reduced and hydrogen is oxidized. B) Oxygen and hydrogen are both C) Oxygen and hydrogen are both reduced D) Oxygen is oxidized and hydrogen A voltaic cell is constructed with two silver-silver chloride electrodes, where the AgCl(s) + e^- rightarrow Ag(s) + Cl^- (aq) E degree = + 0.222 V of chloride ion in the two compartments are 0.0222 M and B) 0.118 C) 0.00222 D) 22.2

Explanation / Answer

22. This is a concentration cell

Eo = 0 V

E = Eo - 0.0592/n logK

    = 0 - 0.0592/2 log(1 x 106-5/0.1)

    + 0.12 V

23. During electrolysis of water,

A)

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