A manufacturing company\'s process takes place in water in a closed container un

Question

A manufacturing company's process takes place in water in a closed container under pressure a For the reaction to take place at 1.15 times 10^2 C, calculate what minimum pressure which you may assume is the vapor pressure of the water at this temperature, this container must be able to withstand using the in For water in this process, you may use Delta H_ = 40.7 kJ/mol and a normal boiling point of 1.00 times 10^2 degree C with R = 8.3145 J/(K middot mol) b. To improve the process's efficiency, engineers determined that the process should be preformed at a pressure of 3.50 atm. The reaction process does not proceed correctly at a temperature of above 1.50 times 10^2 degree C, which means you may assume the vapor pressure of water must be 3.50 atm or less at this temperature. Predict if this is so using the Clausis-Clapeyron equation.

Explanation / Answer

(a)

At normal boiling point, P = 1 atm

Given Calcius - Calpeyron equation,

lnP1 - lnP2 = (deltaH/R)[(1/T2) - (1/T1)]

ln1 - lnP2 = (40.7/0.008314)[(1/388.15) -(1/373.15)]

- lnP2 = - 0.507

P2 = e0.507

P2 = 1.66 atm

(b)

lnP1 - lnP2 = (deltaH/R)[(1/T2) - (1/T1)]

ln1 - lnP2 = (40.7/0.008314)[(1/423.15) -(1/373.15)]

- lnP2 = - 1.55

P2 = e1.55

P2 = 4.71 atm

Pressure is greater than 3.50 atm at this temperature

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