Solid sodium reacts violently with water, producing heat, hydrogen gas, and sodi

Question

Solid sodium reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrogen gas are formed when 48.7 g of sodium are added to water? 2Na + 2H_2O + 2NaOH + H_2 What is the mole ratio of D to A in the generic chemical reaction? 2A + B rightarrow C + 3D How many grams of CO are needed to react with an excess of Fe_2O_3 to produce 209.7 g Fe? Fe_2O_3(s) + 3CO(g) rightarrow 3CO_2(g) + 2Fe(s) If 8.00 mol of NH_3 reacted with 140 mol of O_2, how many moles of H_2O will be produced? 4NH_3(g) + 7O_2(g) rightarrow 4NO_2 + 6H_2O(g)

Explanation / Answer

27) How many molecules of hydrogen gas are formed when 48.7 g of sodium are added to water

2Na + 2H2O -----> H2 + 2Na(OH)

48.7/23 = 2.12 moles of sodium

2.12/2 = 1.06 moles of hydrogen

1.06 X 6.02x10^23 = 1.204x10^24 molecules of hydrogen.

28) What is the mole ratio of D to A in the generic chemical reaction?
   2A + B ---> C + 3D
3 : 2 (3 to 2)
Reason Every 3 moles of D is formed when 2 moles of A reacts.

29) how many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7 g Fe
   Fe2O3(s)+3CO(g) = 3CO2(g) +2Fe(s)

Moles Fe = 209.7 g / 55.847 = 3.75
the ratio between CO and Fe is 3 : 2
Moles CO needed = 3.75 x 3 / 2 = 5.63
Mass CO = 5.63 mol x 28.01 g/mol =157.7 g

30) If 8.00 mol of NH3 reacted with 14.0 mol of O2. how many moles of H2O will be produced

2NH3(g)+7O2(g)4NO2(g)+6H2O(l)

Notice that you need 2 moles of ammonia to react with 7 moles of oxygen gas in order to produce
4 moles of nitrogen dioxide and 6 moles of water.

We have initial 8.00 mol of NH3 and 14.0 mol of O2, So the limiting reagent is O2.
So, the no. moles of H2O = 2x 6 moles = 12 moles of H2O.

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