A galvanic cell is powered by the following redox reaction: 3 Fe^3+ (aq) + Cr(OH

Question

A galvanic cell is powered by the following redox reaction: 3 Fe^3+ (aq) + Cr(OH)_3 (s) + 5 OH^- (aq) rightarrow 3 Fe^2+ CrO_4^2- (aq) + 4 H_2O(l) Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from Write a balanced equation for the half-reaction that takes place at the cathode. Write a balanced equation for the half-reaction that takes place at the anode. Calculate the cell voltage under standard conditions. Round your answer to 2 decimal places.

Explanation / Answer

At cathode : 3Fe3+ (aq) + 3e- (aq) ---> 3Fe2+ (aq)

at anode : Cr(OH)3 (s) + 5 OH- (aq) ----> CrO4^2- (aq) + 4H2O (l) + 3e- (aq)

Eo cell= Eo ( cathode half reduction potential ) - Eo ( anode half reduction potential )

    = Eo ( fe3+/Fe2+) - Eo ( CrO42- /Cr(OH)3 ,OH-)

      = 0.77- ( -0.13)                 ( since table is not provided , values taken from web)

       = 0.90

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.