Calculate the Weight in grams of each of the following moles: Show calculations

Question

Calculate the Weight in grams of each of the following moles: Show calculations in the space below: (a) three moles of potassium (b) two moles of silver nitrate (c) five moles of silver chloride (d) four moles of sodium bicarbonate (e) six moles of calcium (f) one mole of sodium nitrate For each of the following reactions, write a balanced equation and calculate how many grams of the second reactant are necessary to completely react with 85.5 g of reactant. (i) AgNO_3(aq) + CaCl_2(aq) rightarrow AgCl(s) + Ca(NO_3)_2(aq) (ii) MgCO_3(aq) + AlCl_3(aq) rightarrow MgCl_2(aq) + Al_2(CO_3)_3(aq) (iii) Ba(s) + Cl_2(g) rightarrow BaCl_2(s) (iv) NaOH(aq) + HCl(aq) rightarrow NaCl(aq) + H_2O(I) (v) Sr(s) + O_2(g) rightarrow SrO(s) (vi) KOH(aq) + NaCl(aq) rightarrow KCL(aq) + NaOH(aq) (vii) CaO(s) + CO_2(g) rightarrow CaCO_3(s) (viii) HNO_3(aq) + Li(s) rightarrow LiNO_3(aq) + H_2(g) (ix) Mg(s) + H_2SO_4(aq) rightarrow MgSO_4(aq) + H_2(g) (x) Al_2O_3(s) + K_2So_4(aq) rightarrow K_2O(s) + Al_2(SO_4)_3(aq)

Explanation / Answer

Ans a) molar mass of potassium = 39.1 g/mol

So 3 moles = 39.1 × 3 = 117.3 g

B) molar mass of silver nitrate = 169.87g/mol

So 2 moles = 339.74 g

C) molar mass of silver chloride = 143.32 g/mol

5 moles = 716.6 g

D) molar mass of sodium bicarbonate = 84.007 g/mol

4 moles of it = 336.028 g

E) molar mass of calcium = 40.078 g/mol

Six moles of it = 240.468 g

F) molar mass of silver nitrate = 169.87 g/mol

So 1 mole of it = 169.87 g

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