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A chemical equation may be balanced by the manipulation of which of the followin

ID: 531305 • Letter: A

Question

A chemical equation may be balanced by the manipulation of which of the following? Subscripts coefficients catalyst phases What of the following solutions has has the highest concentration of solute? 1.0 mol solute in 200 mL solvent 2.0 mol solute in 500 mL solvent 3.0 mol solute in 1 L solvent 4.0 mol solute in 1.5 L solvent A pharmacist mixes together20 g of crystals of compound A and 10g of crystals of compound B. The mixture is then dissolved in 120 mL of water to make cough syrup. The mixture will most likely dissolve fastest under which of the following sets of conditions? A student made a homogeneous mixture of water and salt. Which of the following statements applies to this homogeneous mixture? This mixture is a solution. This mixture is a pure substance. The salt is not evenly distributed throughout this mixture. The salt chemically combines with the water in this mixture. (NH_4)_3 PO_4 When of the following gives the correct number of atoms of each kind of element present in the compound whose formula is given above? 1 N, 4H, 3P, 4O 1 N. 4H, 4P, 4O 3N, 12H, 1 P, 4 O 3N, 7H, 4P, 4 O Use the information below to answer the question that follows. Carefully rinse the weighing dish with distilled water into the volumetric flask. Weigh and transfer calculated mass of the salt into a volumetric flask. Cap and shake flask to mix solution well. Top the flask up to the mark with distilled water. Which of the following, lists the steps for preparing a standard solution in the correct order? I, II, III, Iv III, II, I, IV II, I, IV, III III, IV, I, II

Explanation / Answer

6. Anwser is option B.

By changing the coefficients of molecules, a chemical equation will be balanced equation. However, by changing the subscripts, substance will be changed and equation will be incorrect.

7. Concentration of solute = (moles of solute)/( volume of Solvent in liter)

When 1 mole of solute in 200 ml of solvent then concentration = 1mol/ 0.2 L => 5 mol/liter

When 2 mole of solute in 500 ml of solvent then concentration = 2mol/ 0.5 L => 4 mol/liter

When 3 mole of solute in 1 L of solvent then concentration = 3mol/ 1 L => 3 mol/liter

When 4 mole of solute in 1.5 L of solvent then concentration = 4mol/ 1.5 L => 2.67 mol/liter

Thus option A is correct answer

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