Calculate the mass percent (m/m) of a solution prepared by dissolving 41.59 g of

Question

Calculate the mass percent (m/m) of a solution prepared by dissolving 41.59 g of NaCl in 150.6 g of H2O.

Express your answer to four significant figures.

Part B

Vinegar is a solution of acetic acid in water. If a 325 mL bottle of distilled vinegar contains 16.5 mL of acetic acid, what is the volume percent (v/v) of the solution?

Express your answer to three significant figures.

Part C

Calculate the mass/volume percent (m/v) of 24.0 g NaCl in 65.0 mL of solution.

Express your answer to three significant figures.

Part D

Calculate the molarity (M) of 155.2 g of H2SO4 in 1.150 L of solution.

Express your answer to four significant figures.

Explanation / Answer

A)

(m/m)% = mass of NaCl * 100 / total mass

= 41.59*100/(41.59+150.6)

= 21.64 %

Answer: 21.64 %

B)

(V/V)% = volume of acetic acid * 100 / total volume

= 16.5*100/325

= 5.08%

Answer: 5.08 %

C)

(m/V)% = mass of NaCl * 100 / volume of solution

= 24.0*100/65.0

= 36.9%

Answer: 36.9 %

D)

Molar mass of H2SO4,

MM = 2*MM(H) + 1*MM(S) + 4*MM(O)

= 2*1.008 + 1*32.07 + 4*16.0

= 98.086 g/mol

mass,m = 155.2 g

number of mol,

n = mass/molar mass

= 155.2/98.086

= 1.582 mol

volume , V = 1.150 L

Molarity,

M = number of mol / volume in L

= 1.582/1.15

= 1.376 M

Answer: 1.376 M

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