Copper can be cemented onto iron particles by the reaction. Cu^2+ + Fe = cu + Fe

Question

Copper can be cemented onto iron particles by the reaction. Cu^2+ + Fe = cu + Fe^2+. A dilute copper solution containing 0.50 g/L of copper is flowed continuously at a rate of 1 m^3/h through a stirred tank reactor of volume 10 m^3 containing 10 kg of suspended spherical iron particles with a diameter of 1mm. The mass transfer coefficient of Cu^2+ is 6 times 10^-3 cm s^-1 (i) Calculate the concentration of copper ions in the discharge solution (solution leaving the reactor). You may need some of the information given below. (ii) What factors would you change to improve the reaction rate? (iii) Briefly describe how you would test the validity of the mass transfer coefficient you used in the calculation. Total surface area = 6m/(rho d), d is the particle diameter rho_S = 7.9 g cm^-3 is the density of the solid particles and rho_L = 1.0 g cm^-3 is the density of the solution, C = {C_o/(1 + kA/v)}

Explanation / Answer

(i) Calculate Total surface area, A = 6m/d = 6 *1000gm / (7.9 gm cm-3 * 0.1 cm)
   A = 7594.9367 cm2 = 0.7595 m2
Co = (0.50 gm / 63.546 gm/mol )/L = 7.8683*10-3 mol/L
v = 1m3 / hr = 2.7778*10-4 m3/sec
C = Co / (1+kA/v )
C = 7.8683*10-3 / (1+ (0.06*0.7595 / 2.7778*10-4)) = 4.7672*10-5 M

(ii) Change the ratio of intial concentrationto final concentration, modifications in volumetric
   flow rate
(iii) If the data yields correct correlation between the given quantities then the value of
   mass transfer coeffcient will be valid.

(ii)

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