1)In a GC-separation of a mixture of three compounds consisting of 1 mol A, 1 mo

Question

1)In a GC-separation of a mixture of three compounds consisting of 1 mol A, 1 mol B, and 1 mol C, the peak area (integral) produced by the response of the detector is:

Compound A: 50      Compound B: 20         Compound C: 10        

The separation of a second mix of the same compounds with an unknown composition leads to the following peak areas:

            Compound A: 20      Compound B: 400       Compound C: 10        

Please calculate the response ratio of your compounds if you choose compound C as your standard. What is the molar composition of the second mixture (show your calculations)?

Explanation / Answer

Compound C being standard

In first mixture,

response factor for A and C = 50/10 = 5

response factor for B and C = 20/10 = 2

In the second mixture,

molar composition of A = 5(20/x) = (10/1) = 10

molar composition of B = 2(400/x) = (10/1) = 80

molar composition of C = 10

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