The standard heat of the reaction CaC_2 (s)+ 5H_2 O(l) rightarrow CaO (s) + 2CO_

Question

The standard heat of the reaction CaC_2 (s)+ 5H_2 O(l) rightarrow CaO (s) + 2CO_2 (g) + 5H_2 (g) is Delta H^9)t = 69.36 kJ/mol What should be your strategy to keep the above reaction temperature constant? (a) Supply heat to keep the temperature constant? (b) Remove heal to keep the temperature constant? (c) Add catalyst to control the reaction (d) Leave it untouched to keep the temperature constant Referring to above reaction in question (1), what can you understand about the break the molecular bonds of the reactants and that released when the product bonds to (a) The energy required to break the reactant bonds is less than the energy product bonds are formed. (b) The energy required to break the reactant bonds is equal to the energy product bonds are formed. (c) The energy required to break the reactant bonds is more than the energy product bonds are formed. (d) Both the above statement (a) and (b) are true.

Explanation / Answer

Ans 1. A) supply heat to keep temperature constant

The reaction in the question mentioned has positive standard heat of the reaction, that means the reaction is endothermic.

The product absorbs heat from the surroundings and the temperature goes down , to keep the temperature constant , you must add heat to the system.

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