The standard heat of the reaction CaC_2 (s)+ 5H_2 O(l) rightarrow CaO (s) + 2CO_

Question

The standard heat of the reaction CaC_2 (s)+ 5H_2 O(l) rightarrow CaO (s) + 2CO_2 (g) + 5H_2 (g) is Delta H^9)t = 69.36 kJ/mol What should be your strategy to keep the above reaction temperature constant? (a) Supply heat to keep the temperature constant? (b) Remove heal to keep the temperature constant? (c) Add catalyst to control the reaction (d) Leave it untouched to keep the temperature constant Referring to above reaction in question (1), what can you understand about the break the molecular bonds of the reactants and that released when the product bonds to (a) The energy required to break the reactant bonds is less than the energy product bonds are formed. (b) The energy required to break the reactant bonds is equal to the energy product bonds are formed. (c) The energy required to break the reactant bonds is more than the energy product bonds are formed. (d) Both the above statement (a) and (b) are true.

Explanation / Answer

(1)

The picture is blurred so it is not clear whether the dHf is+ve or -ve

I assume that it is -ve.

This means that heat is given out by the reaction. So in order to keep the reaction temp constant, we need to remove this extra heat from the system. So correct option is (B)

(2)

(A)The energy required to break the reactant bonds is less than the energy released by the formation of product bonds.

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