Table 1: Applied Force Required to Slide Cup Cup Material Force Applied F 1 m 1
ID: 534 • Letter: T
Question
Table 1: Applied Force Required to Slide Cup
Cup Material
Force Applied F1
m1 = 300 g water
Force Applied F2
M2 = 150 g water
F1 / FN1
F2 / FN2
Plastic
Avg:
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Styrofoam
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Paper
F1
m1 = 150 g water
F2
m1 = 100 g water
F1 / FN1
F2 / FN2
Avg:
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Surface Description
Questions:
What happened to your applied force Fapp as you decreased the amount of water in the cup?
Assume the mass to be exactly equal to the mass of water. Calculate the normal force (FN) for 300 g, 150 g, and 100 g. Use these values to compute the ratio of the Applied Force (Fapp) to the Normal Force (Fn). Place these values in the rightmost column of Table 1.
What do these last two columns represent? What is the ratio of the normal forces F1 / F300? Compare this to your values for F2/ F150, and F3/F100. What can you conclude about the ratio between the Force Normal and the Force Friction?
FN= mg
FN (300 g) = _________kg
Cup Material
Force Applied F1
m1 = 300 g water
Force Applied F2
M2 = 150 g water
F1 / FN1
F2 / FN2
Plastic
Avg:
Avg:
Avg:
Avg:
Styrofoam
Avg:
Avg:
Avg:
Avg:
Paper
F1
m1 = 150 g water
F2
m1 = 100 g water
F1 / FN1
F2 / FN2
Avg:
Avg:
Avg:
Avg:
Surface Description
Explanation / Answer
5. Yes, because an increase in ? produces a corresponding increase in F, thus, the greater the value of ?, the more force is required to overcome friction.
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