The standard free energy change for the hydrolysis of ATP is -30.5 kJ. ATP( a q

Question

The standard free energy change for the hydrolysis of ATP is -30.5 kJ.
ATP(aq)+H2O(l)ADP(aq)+Pi(aq)
In a particular cell, the concentrations of ATP, ADP, and Piare 0.0036 M , 0.0019 M , and 0.0040 M , respectively.

Part A

Calculate the free energy change for the hydrolysis of ATP under these conditions. (Assume a temperature of 298 K.)

The standard free energy change for the hydrolysis of ATP is -30.5 kJ.
ATP(aq)+H2O(l)ADP(aq)+Pi(aq)
In a particular cell, the concentrations of ATP, ADP, and Piare 0.0036 M , 0.0019 M , and 0.0040 M , respectively.

Part A

Calculate the free energy change for the hydrolysis of ATP under these conditions. (Assume a temperature of 298 K.)

Explanation / Answer

deltaG= deltaGO+RT*lnQ

T= temperature in K= 298K

Q= Reaction coefficient= [Pi][ADP]/[ATP]

= 0.0040*0.0019/0.0036=0.00211

lnQ= ln(0.00211)=-6.16

deltaG= -30.5*1000-8.314*298*6.16=-45762 joules= -45.762 Kj

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.