If a student\'s hand is expensed to a basic solution with a pH = 13, what should

Question

If a student's hand is expensed to a basic solution with a pH = 13, what should be ? (A) Wipe off the excess base with paper (B) Sprinkle the hand with baking (C) Rinse the hand in a (D) Rinse the hand in copies amounts of water. A neutral atom of potassium-39 - (A) 19 protons and 39 electrons (B) 20 protons and 19 neutrons (C) 19 electrons, 19 protons and 20 neutrons (D) 20 electrons, 19 protons and 19 neutrons A gas cylinder is filled with 5.00 moles of oxygen gas at 300.0K. The piston is compressed to yield a pressure of 400.0 kPa. What is the volume inside the cylinder? (A) 112 dm^3 (B) 2.22 dm^3 (C) 31.2 dm^3 (D) 55.4 dm^3 What is the molar mass of Co_2 (CO_3)_3 ? (A) 274 g/mol (B) 298 g/mol (C) 204 g/mol (D) 250 g/mol The correct formula of an ionic compound containing Ca^2+ and PO_4 ^3- is - (A) CaPO_4 (B) Ca (PO_4)_2 (C) Ca_2 (PO_4)_3 (D) Ca_3 (PO_4)_2 The energy required to boil a liquid into a gas is called- (A) heat of fusion (B) heat of vaporization (C) heating curve (D) triple point

Explanation / Answer

question 25 is not clearly visible

26)

Atomic number of potassium is 19

So, there will be 19 protons

Since atom is neutral,

number of electrons will be same as number of protons

number of electrons = 19

For potassium-39, mass number = 39

So,

number of neutrons = mass number - atomic number

= 39-19

= 20

Answer: C

27)

n = 5.00 moles

T = 300.0 K

P = 400.0 kpa

R = 8.31 Kpa.dm^3/moles.K

use:

P*V = n*R*T

400.0 kpa * V = 5.00 moles * 8.31 Kpa.dm^3/moles.K * 300.0 K

V = 31.2 dm^3

Answer: C

I am allowed to answer only 1 question at a time

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