A student studied the clock reaction described Experiment 21 Advance Study Assig

Question

A student studied the clock reaction described Experiment 21 Advance Study Assignment: Rates of Chemical Reactions, ll. A Clock Reaction 1. A student studied the clock reaction described in this experiment. She set up Reaction Mixture 4 by mixing 10 mL, 0.010 M K 10 mL M Nazsao, 10 mL o o40 M KBro, and 20 mL, o.10 M HCI 0.001 using the procedure given. It took about 21 seconds for the color to tum blue. a. concentrations each in the reacting mixture by realizing that the number She found the of reactant of moles of each reactant did when was mixed with the others but that its not change that reactant concentration did. For any reactant A The volume of the mixture was 50 mL. Revising the above equation, she obtained MA misture MA ueckx Find the concentrations of each reactant in the reaction mixture, using the equation above: 1 M: [Bro, M IH 1- M b. What was the relative rate of the reaction (1000)? isec c. Knowing the relative rate of reaction for Mixture 4 and the concentrations of and in that mixture, she was able to set up 5 for the relative rate of the reaction. The only quantities that remained unknown were k'. and p. Set up Equation 5 as she did, presuming she did it properly. 2. For Reaction Mixture 1. the student found that seconds were required. On dividing Equation 5 for 85 Reaction Mixture I by Equation 5 for Reaction Mixture 4, and after canceling out the common terms (k' and terms in ll land [Bro, D, she got the following equation: 11.8 (0,020Y 48 (0.040 Recognizing that 11.848 is about equal to K. she obtained an approximate value for p. What was that value? (continued on following page)

Explanation / Answer

Ans a) For [I-]

Vmixture = 50ml

Vstock =10ml

Mstock =0.010

MMixture (I-) = Mstock x Vstock / VMixture

                  = 0.010x10/50

                  =0.0020M

Therefore [I-] = 0.0020M

Again

For [BrO3-]

Vstock = 10ml

Mstock =0.040M

[BrO3- ] = 0.040x10/50

= 0.008M

Again for [H+ ]

Vstock = 20ml

Mstock =0.1M

[H+] = 0.1x20/50

   = 0.04M

Ans b) Relative rate = 1000/t

Here t= 21sec

therefore relative rate = 1000/21 I/sec

= 47.61I/sed

Ans c) Now The equation will be

Relative rate = k[I-]m[BrO3-]n[H+]p

47.67 =k[0.002]m [0.008]n[0.04]p is the required equation

Ans 2) The required equation is

11.8/48 = (0.020/0.040)p =(1/2)p

11.8/48 =(1/2)p

0.25 =(0.5)p

(0.5)2 =(0.5)p

p=2

Therefore order of the reaction with respect [H+]=2

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