A chemist is tasked with determining the concentration of nickel for a water sam

Question

A chemist is tasked with determining the concentration of nickel for a water sample drawn from a well next to a nickel mine. To analyze the sample using atomic absorbance spectroscopy (AAS), she prepares six samples (0-5) by adding 10.00 mL well water to a 50.00-mL volumetric flask, then adding an increasing volumes of 25.00-ppm nickel solution, diluting the resulting solution to 50.00 mL with 0.1 M HNO3. Following AAS analysis, a graph of absorbance versus ppm nickel standard gave a best-fit line y = 0.0428x + 0.0487. Calculate the ppm nickel in the well water sample.

*** there are no tables / given concetrations, equations must be used- I am not sure the equations. Thank you.

Explanation / Answer

At x= o

y = 0.0487, this absorption is only due to the presence nickel in 10 mL water.

Slope of the line is given as 0.0428

that means 1 ppm diluted to 50 mL will give an absorbance of 0.0428

10 mL solution diluted 50 mL is giving an absorption of 0.0487

since dilution factor is same

0.0487/0.0428 will give the concentration in 50 mL = 1.13 ppm

1.13 ppm is there in 10 mL

1 mL contains 0.113 ppm of Ni

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