1) At a certain temperature, this reaction establishes an equilibrium with the g
ID: 535559 • Letter: 1
Question
1) At a certain temperature, this reaction establishes an equilibrium with the given equilibrium constant, Kc.
3A(g)+2B(g) = 4C(g) Kc=2.93*10^19
If, at this temperature, 1.50 mol of A and 4.00 mol of B are placed in a 1.00-L container, what are the concentrations of A, B, and C at equilibrium?
2)At a certain temperature, 0.318 mol of CH4 and 0.875 mol of H2S is placed in a 3.50 L container.
CH4(g)+2H2S(g)=CS2(g)+4H2(g)
At equilibrium, 14.2 g of CS2 is present. Calculate Kc.
3)At a certain temperature, the equilibrium constant for the following chemical equation is 3.90.
SO2(g)+NO2(g)=SO3(g)+NO(g)
At this temperature, calculate the number of moles of NO2(g) that must be added to 2.31 mol of SO2(g) in order to form 1.10 mol of SO3(g) at equilibrium.
4)At 500 C, hydrogen iodide decomposes according to 2HI(g)=H2(g)+I2(g)
For HI(g) heated to 500 C in a 1.00-L reaction vessel, chemical analysis determined the following concentrations at equilibrium: [H2]=0.363 M, [I2]=0.363 M, and [HI]=3.07 M. If an additional 1.00 mole of HI(g) is introduced into the reaction vessel, what are the concentrations of [HI], [H2], and [I2] after the new equilibrium has been reached?
Explanation / Answer
Q1)
3A(g)+2B(g) = 4C(g) Kc=2.93*10^19
If, at this temperature, 1.50 mol of A and 4.00 mol of B are placed in a 1.00-L container, what are the concentrations of A, B, and C at equilibrium?
initially
[A] = 1.5
[B] = 4
[C] = 0
in equilibrium
[A] = 1.5 -3x
[B] = 4 -2x
[C] = 0 + 4x
and we know: 2.93*10^19
K = [C]^4/([A]^3 * [B]^2)
2.93*10^19 = (4x)^4 / ((1.5 -3x)^3 * (4 -2x)^2)
Solving for x:
2.93*10^19 = (4x)^4 / ((1.5 -3x)^3 * (4 -2x)^2)
x = 0.499999 (neares th)
[A] = 1.5 -3x = 1.5-3*0.499999 = 3*10^-6 M
[B] = 4 -2x = 4-2*0.499999 = 3.000002 M --> 3 M approxx
[C] = 0 + 4x = 4*0.499999 = 1.999996 M --> 2 M approx
Note that x is very sensitive with respect to x, since it is a very high K value
in pracitcal terms, we will assume [A] goes to compeltion, i.e [A] = 0
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