Suppose that a person eats a diet of 2125 Calories per day. Part A Convert this
ID: 536008 • Letter: S
Question
Suppose that a person eats a diet of 2125 Calories per day.
Part A
Convert this energy into J.
Express your answer using four significant figures.
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Part B
Convert this energy into kJ.
Express your answer using four significant figures.
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Part C
Convert this energy into kWh.
Express your answer using four significant figures.
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The gas in a piston (defined as the system) is warmed and absorbs 645 J of heat. The expansion performs 350 J of work on the surroundings.
Part D
What is the change in internal energy for the system?
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A system releases 400 kJ of heat and does 105 kJ of work on the surroundings.
Part E
What is the change in internal energy of the system?
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Suppose that a person eats a diet of 2125 Calories per day.
Part A
Convert this energy into J.
Express your answer using four significant figures.
JSubmitMy AnswersGive Up
Part B
Convert this energy into kJ.
Express your answer using four significant figures.
kJSubmitMy AnswersGive Up
Part C
Convert this energy into kWh.
Express your answer using four significant figures.
kWhSubmitMy AnswersGive Up
The gas in a piston (defined as the system) is warmed and absorbs 645 J of heat. The expansion performs 350 J of work on the surroundings.
Part D
What is the change in internal energy for the system?
E = JSubmitMy AnswersGive Up
A system releases 400 kJ of heat and does 105 kJ of work on the surroundings.
Part E
What is the change in internal energy of the system?
E = kJSubmitMy AnswersGive Up
Explanation / Answer
(A) 1 cal = 4.18 joule
2125 cal = 8882.5 joule
up to four significant number it will be 8882 joules.
(B) 1 joule = 1/1000 Kilojoule
8882 joule = 8.882 KJ
up to four significant number will be same 8.882
(C) 1 kjoule = 2.777778 x 10-4 KW-h
8.882 KJ = 8.882 x 2.777778 x 10-4 = 2.467 x 10-3 Kw-h
(D) change in internal energy = q + w
q will be positive as heat absorbed by the system
w will be negative as work done by the system on the surrounding
= 645 - 350
= 295 joule
(e) as heat released, therefore, it will be in negative means -400 kJ and work will also be negative because done by system change in internal energy will be = q+w
= - 400 - 105
= - 505 KJ
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