aboratory 7 Ionization & Classification of Acids, Bases and Salts NAME: DATE: IN
ID: 536616 • Letter: A
Question
aboratory 7 Ionization & Classification of Acids, Bases and Salts NAME: DATE: INSTRUCTOR: SECTION: WORKSHOP: CONDUCTIVITY OF SOLUTIONS. Answer the following questions during the lab time. 1. The pH of a solution of 0.1M HNO,? 2. The pH of a solution of 0.00001M KOH 3. The pH and POH of a solution of 0.01M HBr? 4. The pH and POH of a solution of 0.00001M KOH 5. the following substances as strong electrolyte (SE), weak electrolyte (WE) and Classify non-electrolyte (NE) a. Glucose, CH b. Carbon tetrachloride, CCI c. Sodium iodide, Nal d. Hydrochloric acid, HCl e. Vinegar f Iron (III) Chloride, FeCl, g. Ethanol CH,OH h, Nitric Acid, HNO, i. Ammonium Hydroxide, NH40HExplanation / Answer
Q1.
assume HNO3 is strong acid, since NO3- ionizes completely
so
HNO3 <-> H+ + NO3-
and
pH = -log([H+])
then
[HNO3] = [H+] = 0.1 M
pH = -log(0.1) = 1
Q2.
for KOH, assume this is a base so
KOH --> K+ + OH-
pOH = -log([OH-])
[OH-] = [KOH] = 0.00001 M
pOH = -log(0.00001 ) = 5
then
from the equilibrium of water at T = 25°C
14 = pH + pOH
pH = 14- pOH = 14-5 = 9
pH = 9 for KOH
Q3.
for HBr
[H+] = [HBr] = 0.01 M
pH = -log(H) = -log(0.01) = 2
so
pOH = 14-pH = 14-2 = 12
Q4
for KOH:
[OH-] = [KOH] = 0.00001
pOH = 5
pH = 14-5 = 9
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.