The entire human genome consists of about 3.2 Gb (gigabase =billion nucleotides)
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Question
The entire human genome consists of about 3.2 Gb (gigabase =billion nucleotides) or 3200 Mb (Megabase = million nucleotides) of DNA. Adjacent bases in DNA are about 0.34 nm (1 nanometer = 1/1,000,000 mm) apart. If all of the DNA in the human genome were lined up in a single chromosome, about how far in mm would the DNA stretch?
Assuming that only about 2% of the human genome consists of coding sequences, how many nucleotides would be in that 2%? How long in mm would a single piece of DNA containing ONLY the coding sequences be?
The human beta globin gene contains both exons and introns. How many exons does it have? How many introns? If you had a gene with 22 exons, how many introns would you predict that it has?
Explanation / Answer
The DNA will strech to 1088 mm
The coding sequence of human gene will be 640 Mb.
The coding sequence will stretch 21.76 mm
Three exons and two introns are present in beta globin gene.
Number of introns cannot be predicted with exons. It will vary between genes
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