write the electron configuration for the neutral atom or ion indicated in the sp
ID: 538578 • Letter: W
Question
write the electron configuration for the neutral atom or ion indicated in the space provided. It is OK to use the condensed notation in which the noble-gas core is represented using the appropriate symbol in square brackets. For example, the electron configuration of Al is [Ne]3s23p1
(a) Write the electron configuration of Sn (Z = 50):
(b) Write the electron configuration of Ni2+ (Z = 28):
(c) Write the electron configuration of Te2– (Z = 52):
(d) Write the electron configuration of Os (Z = 76):
(e) Write the electron configuration of Pb4+ (Z = 82):
Explanation / Answer
(a) electronic configuration of Sn(50)
belongs to IV group or 14th group-
Valence electronic configuration is [Kr] 4d10 5s2 5p2 [ atomic number of Kr=36, 36+10+2+2=50]
(b) electronic configuration of Ni+2
Ni atomic number is 28- [Ar] 4s2 3d 8 [ atomic number of Ar=18, 18+2+8=28]
electronic configuration of Ni +2 = [Ar] 4s0 3d 8 [remove two electrons in the outer shell 4s]
(c) Electronic configuration of Te-2
Tellurium belongs to VI group or 16th group
valence electronic configuration is [Kr] 4d10 5s2 5p4 [Kr=36, 36+10+2+4=52]
electronic configuration of Te(-2) = [Kr] 4d10 5s2 5p6 ( increase two electrons in 5p shell]
(d) electronic configuration of Osmium-(76)
Os is a d-block element and belongs to 5d series.
electronic configuration is = [Xe] 4f14 6s2 5d6 [ Xe=54, 54+14+2+6= 76]
(e) electronic configuration of Pb(+4)
Lead belongs to IV A group or 14th group
electronic configuration is - [Xe] 4f14 5d 10 6s2 6p2 [ Xe=54, 54+14+10+10+2+2= 82]
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