In the polymerization process of Ethylene (C_2H_4). Hydrogen peroxide (H_2O_2) m

Question

In the polymerization process of Ethylene (C_2H_4). Hydrogen peroxide (H_2O_2) molecule acts as the initiator and terminator of polyethylene chains. Hydrogen, Oxygen and Nitrogen possess atomic weights of 1, 16, and 12 g/mol respectively. The number of C_2H_4 molecules and the number of chains involved in polymerization of 10.000g/mol of polyethylene respectively is: (a) 28 and 34 (b) 357 and 294 (c) 1.7 times 10^-22 and 2.15 times 10^-26 (d) 2.15 times 10^26 and 1.7 times 10^22 (e) 2.15 times 10^-26 and 1.7 times 10^-22

Explanation / Answer

10,000 g/ mol of Polyethylene

Mol. Wt. C2H44= 2(12) + 4(2) = 28 g/mol

Mol. Wt. H202 = 2(16) + 2(1) = 34 g/mol

The number of C2H2 molecules -

Degree of polymerization = 10,000g/mol/28 g/mol = 357

The number of C2H2 molecules = Degree of polymerization x Avogadro number

The number of C2H2 molecules = 357 x 6.022 x 10^23

The number of C2H2 molecules = 2.15 x 10^26

Assuming 1 molecule of H2O2 is consumed per molecule of Polyethylene The number of C2H2 molecules -

Degree of polymerization of H2O2 = 10,000g/mol/34 g/mol = 294

The number of H2O2 molecules = Degree of polymerization x Avogadro number

The number of H2O2 molecules = 294 x 6.022 x 10^23 = 1.77 x 10^23

DP =2.15 x 10^26/1.77 x 10^23 = 12147

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