Chemistry: Fundamentals and Principles presented by Sapling Learning A common la

Question

Chemistry: Fundamentals and Principles presented by Sapling Learning A common laboratory method for preparing oxygen gas involves decomposing potassium chlorate (KCIOs) as shown by the following reaction 2KC10, -> 2KCI + 30, Based on this equation, how many grams of KCIOs must be decomposed to yield the following amounts of the products? a) to produce 5.35 mol KCI b) to produce 45.7g 2 Number DE KCIO, g Kcio g Kcio Hint Previous ®Give up & View Solution 0 Check AnswerNext Exit Backspace 8 9 0 5 6 O P

Explanation / Answer

a)

According to balanced equation

mol of KClO3 required = moles of KCl

= 5.35 mol

mass of KClO3 = number of mol * molar mass of KClO3

= 5.35*122.55

= 656 g

Answer: 656 g

b)

Molar mass of O2 = 32 g/mol

mass of O2 = 45.7 g

molar mass of O2 = 32 g/mol

mol of O2 = (mass)/(molar mass)

= 45.7/32

= 1.4281 mol

According to balanced equation

mol of KClO3 required = (2/3)* moles of O2

= (2/3)*1.4281

= 0.9521 mol

mass of KClO3 = number of mol * molar mass of KClO3

= 0.9521*122.55

= 117 g

Answer: 117 g

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.