Chemistry Help? Part (1) Given that the ionic compounds shown are completely dis

Question

Chemistry Help?

Part (1) Given that the ionic compounds shown are completely dissolved in water, which of the following is the most likely compound represented by the molecular view in Beaker A?

Na2SO4

PbI2

CaCl2

KBr

Part (2) Given that the ionic compounds shown are completely dissolved in water, which of the following is the most likely compound represented by the molecular view in Beaker B?

Na2CO3

Cu(NO3)2

BaSO4

FeCI3

Identify the precipitate and spectator ions for any reaction that will result when beakers A and B are mixed.

CaCO3 is the precipitate, and K+ and Br? are the spectator ions.

CaCO3 is the precipitate, and Na+ and Cl? are the spectator ions.Ba

CO3 is the precipitate, and K+ and Br? are the spectator ions.

CuSO4 is the precipitate, and Na+ and Cl? are the spectator ions.

Explanation / Answer

Part a.

Since beaker A has ions with +2 cationic state and -1 anionic state,so from the options which satisfy such condition is

CaCl2 as Ca has +2 state and Cl is in -1 state .

Part b.

Similarly in beaker B ,ions are there in -2 anionic state and +1 cationic state ,so only choice from the options is

Na2CO3 as Na is in +1 cationic state and CO3 is in -2 anionic state.

Part c

When beaker A and beaker B solutions are mixes which is Na2CO3 and CaCl2,then resulting precipitate will be CaCO3 and spectator ions will be Na+ and Cl- ions according to the reaction

Na2CO3 (s) +CaCl2(aq) --->CaCO3(s) ppt +Na+ (aq) +Cl- (aq)

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