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Bookmarks Window Help saplinglearning.com Search Textbo.. https://www.e picasso cubis... 8 Things You Jump to... Map Sapling Learning Nitrogen and hydrogen combine at high temperature, in the presence of a catalyst, to produce ammonia. N,(g)+3H2(g) 2NH3(g) sume 0.210 mol of N2 and 0.658 mol of H2 are present initially. Number After complete reaction, how many moles of ammonia are produced? mol Number How many moles of He reain?D 10 mol Number How many moles of N2 remain? mol O hydrogen O nitrogen What is the limiting reactant? Hirt bout uscree privacy policy termis of use MacBook Air

Explanation / Answer

1)

Balanced chemical equation is:

N2 + 3 H2 ---> 2 NH3

1 mol of N2 reacts with 3 mol of H2

for 0.21 mol of N2, 0.63 mol of H2 is required

But we have 0.658 mol of H2

so, N2 is limiting reagent

we will use N2 in further calculation

According to balanced equation

mol of NH3 formed = (2/1)* moles of N2

= (2/1)*0.21

= 0.420 mol

Answer: 0.420 mol

b)

According to balanced equation

mol of H2 reacted = (3/1)* moles of N2

= (3/1)*0.21

= 0.63 mol

mol of H2 remaining = mol initially present - mol reacted

mol of H2 remaining = 0.658 - 0.63

mol of H2 remaining = 0.028 mol

Answer: 0.028 mol

c)

N2 is limiting . So no N2 is remaining

Answer: mol

d)

Answer: Nitrogen

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