Formation Reactions Correct The standard heat of formation, }, is defined as For

Question

Formation Reactions Correct The standard heat of formation, }, is defined as For both of these of AH ng like the enthalpy change for the formation of one mole of substance from its constituent states. Thus, f the reaction would not be equal to H for the product. t for the product were not 1, or if the reactants were not hen states have = 0, Heat of formation values can be used to calculate the enthalpy change of any reaction. Part B 2N0(g) + O2 (g) 2NO2 (g) with heat of formation values given by the following table: CsH4 (g) + 502 (g)3CO2 (g) + 4H20(g) Substance (kJ/mol) Substance (J/mol) C3Hs (g) 104.7 CO2(8)-3935 H2O(g)241.8 Calculate the enthalpy for the combustion of 1 mole of propane. Express your answer to four significant figures and include the appropriate units NO(g) 902 O,(8) NO2(8) 33.2 Then the s A, (products)-Ar(reactants) 2(33.2) -114 kJ Hrx.- -12(90.2) + Hints = Hron . | Value | Units

Explanation / Answer

Given:

Hof(C3H8(g)) = -104.7 KJ/mol

Hof(O2(g)) = 0.0 KJ/mol

Hof(CO2(g)) = -393.5 KJ/mol

Hof(H2O(g)) = -241.8 KJ/mol

Balanced chemical equation is:

C3H8(g) + 5 O2(g) ---> 3 CO2(g) + 4 H2O(g)

Ho rxn = 3*Hof(CO2(g)) + 4*Hof(H2O(g)) - 1*Hof( C3H8(g)) - 5*Hof(O2(g))

Ho rxn = 3*(-393.5) + 4*(-241.8) - 1*(-104.7) - 5*(0.0)

Ho rxn = -2043 KJ/mol

Answer: -2043 KJ/mol

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