Calculate the volume of 2.0116 x 10 molecules of NH, gas trapped in a container

Question

Calculate the volume of 2.0116 x 10 molecules of NH, gas trapped in a container at a pressure of 2280.0 mmHg and a temperature of 41.000°C. .)A paintball gun's air-tank is able to handle 3500.0 psi (24131 kPa) until the seal breaks. If the air-tank is filled with compressed air to a pressure of 3000.0 psi (20684 kPa) at a temperature of 24.444 C, determin... a.the pressure inside the air-tank if the paintball gun is brought outside on a hot summer day and the temperature of the gas inside the tank reaches 395°C b. Does the seal break under the conditions of part a? 186

Explanation / Answer

4)

number of mol of gas = number of molecules / Avogadro’s number

= (2.0116*10^23)/(6.022*10^23)

= 0.334 moles

Given:

P = 2280.0 mm Hg

= (2280.0/760) atm

= 3 atm

n = 0.334 mol

T = 41.0 oC

= (41.0+273.15) K

= 314.15 K

use:

P * V = n*R*T

3 atm * V = 0.334 mol* 0.0821 atm.L/mol.K * 314.15 K

V = 2.8715 L

Answer: 2.8715 L

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