At a certain temperature* (probably not 25 °C), the solubility of silver sulfate

Question

At a certain temperature* (probably not 25 °C), the solubility of silver sulfate, Not yet answered Ag2SO, is 0.024 mol/L. Calculate its solubility product constant for this temperature. SIG. FIG. (required because number is small) Marked out of 1.00 Flag question lubility product constants are very temperature sensitive. They are generally reported at 25 °C. Not necessarily using this temperature allows me some flexibility. Answer: At a certain temperature, the solubility of potassium iodate, KIO3, is 33.0 g/L Calculate its solubility product constant for this temperature Not yet answered Marked out of 1.00 P Flag question Answer:

Explanation / Answer

Q1

[Ag2SO4] = 0.024 M

find Ksp given this

Ksp = [Ag+]^2[SO4-2]

[Ag+] = 2*[Ag2SO4] = 2*0.024 = 0.048

[SO4-2] = [Ag2SO4] = 0.024

Ksp = [Ag+]^2[SO4-2]

Ksp = (0.048)^2 * 0.024

Ksp = 0.000055296

Ksp = 5.5*10^-5 (keep only 2 sig fig)

Q2

similarly:

KIO3 = K+ + IO3-

Ksp = [K+][IO3-]

change to molar solubility

mol = masS/M W= 33/214.0010 = 0.1542

Ksp = (0.1542)(0.1542)

Ksp = 0.02377

Ksp = 2.4*10^-2 (keep only 2 sig fig)

Q3

Ksp= [Cd+2][F-]^2

Ksp = (0.077)(0.077*2)^2

Ksp = 0.001826

Keep 2 sigt fig

Ksp = 1.8*10^-3

Q4.

Ksp = [Cu+2][IO3-]^2

7.33*10^-8 = (S)(2S)^2

4S^3 = 7.33*10^-8

S = ((7.33*10^-8)/(4))^(1/3)

S = 0.002636 M

choose 3 sig fig --> 0.00264 M

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