e redox reaction below determine which element is oxdidiznd and which is rodaced

Question

e redox reaction below determine which element is oxdidiznd and which is rodaced osidized and N is reduced s oxidized and O is reduced is oxidized and Cl is reduced is oxidized and N is reduced Nis oxidized and O is reduced d identify the reducing agent in the following chemical reaction A) Fe2+ B) MnO4 C)Ht D) Mn2+ E) Fe3+ 25. What mass of CeH 1206 (glucose) is needed to prepare 0450 L of a 0.650 M solution of glucose in water? A) 0.293 g B) 293 g C) 0.692 g D) 52.7 g E) 125 g 26. A 14.3 g sample of MgCl2 is dissolved in enough water to give 125 mL of solution. What is the chloride lon concentration in this solution? A) 0.150 M B) 0.300 M C) 1.20 M D) 2.40 M E) 0.114 M 27. What volume of concentrated sulfuric acid (18.4 M) is required to make 100.0 mL of a 25 M nitric acid solution? A) 13.6 mL B) 27 mL C) 14 mL D) 6.75 ml E) None of the above 28. During a titration the following data were collected. A 10.0 mL portion of an unknown monoprotic acid solution was titrated with 1.0 M NaOH; 40.0 mL of the base were required to neutralize the sample. How many moles of acid are present in 2.0 liters of this unknown solution? A) 6.0 moles B) 7.0 moles C) 8.0 moles D) 9.0 moles E) None of the above

Explanation / Answer

23)

oxidation number of N increases from negative to 0

So, N is oxidised

oxidation of Cl changes from +1 to -1

So, Cl is reduced

Answer: C

24)

Fe2+ is oxidised to Fe3+

So, this is reducing agent

Answer: A

25)

volume , V = 0.450 L

number of mol,

n = Molarity * Volume

= 0.65*0.45

= 0.2925 mol

Molar mass of C6H12O6,

MM = 6*MM(C) + 12*MM(H) + 6*MM(O)

= 6*12.01 + 12*1.008 + 6*16.0

= 180.156 g/mol

mass of C6H12O6,

m = number of mol * molar mass

= 0.2925 mol * 180.156 g/mol

= 52.7 g

Answer: D

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