Chemistry Chapter 5-Google Chrome ps//session.masteringchemistry.com/myct/itemVi

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Chemistry Chapter 5-Google Chrome ps//session.masteringchemistry.com/myct/itemView?offset-next&assignmentProblemID; 887452 Chanter 5Enthalpies of Reaction Enthalpies of Reaction At one time, a common means of 2KCIO, (s) 2KCI(s) + 302 (g) 1--89.4kJ Part A For this reaction, calculate H for the formation of 1.32 mol of 02 kJ Submit My. Answers Give Up Incorrect; Try Again; 5 attempts remaining Part B For this reaction, calculate H for the formation of 101 g of KCI k.J Submit My Answers Give Up

Explanation / Answer

Part A

From the balanced chemical equation, it is clear that for the production of 3 mol oxygen gas delta H = -89.4 kJ

thus for production of one mole of oxygen gas.

delta H = -89.4/3 = -29.8 kJ

For the production of 1.32 mol oxygen

delta H = -29.8 x 1.32 = -39.336 kJ

Part B

From the balanced chemical equation

delta H for the formation of 1 mole KCl = -89.4/2 = -44.7 kJ

Number of moles of KCl present in 10.1 g = mass of KCl/molar mass of KCl = 10.1/74.5 = 0.1355 moles

delta H for the formation of 10.1 g KCl = 0.1355 x (-44.7) = -6.06 kJ

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