Page 5 A student in another Section made the following observations and obtained
ID: 547089 • Letter: P
Question
Page 5 A student in another Section made the following observations and obtained the (5 pointsg) Reaction I: the amount of concentrated nitric acid HNO, were added until all copper was converted. The student stated that the excess acid would real impact on the recovery of Copper? was apparently too small so, a few additional drops of Reaction I1: upon addition of NaOH the student observed a bright, thick, blae precipitate. The student was not sure about the identity of the copper compound formed. Among the possibilities the student chose 2 Writethe in mala the correct compound: 1-CoppertT) hydroxide? 2-CoppertID) hydroxide? 3-Coppen) oxide? 4-CoppertIL) oxide? Reaction IIl: the student followed the procedure and obtained a black solid that upon several centrifugations and heating yielded the coerect oompound. Write the formela of this compound Im 1-Copper(T) hydroxide? 2-Copper(It) hydroxide? 3-Coppert) oxide? 4-Copper(TI) oxide? Reaction IV: the solid from Reaction IIl was reacted with aqueous sulfuric acid and a clear, transparent blue solution was obtained: [You must balance the equation!) Whatisthenameof compound ion? 1-Coppenti) hydroxide hexahydrate ion? 2-Copperill) hydroxide hesxahydrate ion 3-Copper(t) hexahydrate ion?? 4-Coppen(II) hexahydrate ion? Rsastion V Finally, upon reduction of [Cu(HOl(a, blue) using Magnesium metal, the copper is recovered Balance the equation showing the redection of copper in [QuH:O (aq, bloc) to yield the metalic copperExplanation / Answer
Answer for Reaction I
Cu(s) + HNO3(aq)-------> Cu(NO3)2(aq) +NO2(g) +H2O(l)
If after adding Acid the balance equation should be like:-
Cu(NO3)2 (aq)+2HCl(aq)------>CuCl2(aq)+2HNO3(aq)
However, since none of the product are a gas, water, or a precipitate, this reaction does not actually occure, which can be indication by writing this following reaction
Cu(NO3)2 (aq)+HCl (aq)--------> No reaction.
Hence by addition of acid there is no effect of removing of Cu by the acid.
Answer to Rection II
Upon addition of NaOH, the Copper(II) hydroxide, Cu(OH)2 is formed.
Cu(NO3)2 (aq)+NaOH(aq)-------> Cu(OH)2 (s)+NaNO3(aq)
Answer To Reaction III
After heation the above Copper(II) hydroxide it gives Copper(II)oxide, which formula is CuO.
Cu(OH)2(s) -------> CuO(s)+H2O(l)
Answer to the reaction IV
2CuO(s)+4H3O+(aq)+6H2O(l)-------> 2[Cu(H2O)6]2+
Its name is Copper(II) hexahydrate ion.
Answer to the Reaction V
2[Cu(H2O)6]2+(aq, blue)+ Mg (s,mettalic)--------> 2Cu(s)+Mg2+(aq)+ 12H2O(l)
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