What volume (in mL) of a 0.125 M HNO3 solution is required to completely react w

Question

What volume (in mL) of a 0.125 M HNO3 solution is required to completely react with 39.4 mL or a 0.100M Na2CO3 solution, according to the following balanced chemical equation:

Part A What volume (in mL) of a 0.125 M HNO3 solution is required to completely react with 39.4 mL of a 0.100 M Na2 CO3 solution according to the following balanced chemical equation? Na2CO3 (aq) + 2 HNO3 (aq) 2 NaNO3 (aq) + CO2(g) + H20(1) Express your answer with the appropriate units. V-Value Units Submit My Answers Give Up

Explanation / Answer

Moles of Na2CO3 solution = Molarity*Volume in L

Moles = 0.100M*0.0394L = 0.00394moles

According to the balanced equation-

1 mole of Na2CO3 reacts with 2 mole of HNO3

0.00394 moles of Na2CO3 reacts with=2*0.00394molesHNO3

= 0.00788

Moles of HNO3 = 0.00788moles

Molarity of HNO3 = 0.125M

Volume = moles/Molarity

= 0.00778moles/0.125M = 0.063L

Volume = 63.04mL

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