For part C, please explain reasoning for both a and b. 2M, [B]-1 M, and [C-4M 10

Question

For part C, please explain reasoning for both a and b.

2M, [B]-1 M, and [C-4M 10. (8 points) The system A(g) + B (g)C(g) is at equilibrium with [A] a particular temperature. For each of the following, indicate whether the in a 1-L container at statement is true or false. (Check the appropriate box for each statement) True False Statement a. Starting from the equilibrium state described above, at the instant that 3 moles of B are added to the container, Q > K. b. After 3 moles of B are added to the original system at equilibrium, a new state of equilibrium will be established in which AI = 1 M, [B] = 3M, and [CI = 6M. c. For one of the statements, explain your reasoning and identify which statement you are explaining

Explanation / Answer

Q = [C]/[A][B]

And If Q>K reaction will move towards left and if Q<K reaction will move towards right,that it towards product side

We already have reactants in equilibrium

when we add more [B] then the Q value decreases as new Q = [C]/[A][B+3]  

denominator increases and hence the fraction value decreases

False as it is given Q>K ,which is not correct

b)

As we know that equilibrium constant ,does not change,if temperature is constant

initial K = [C]/[A][B] = 4/2 x 1 = 2

now when B = 1+3 = 4

new [A] ,[B] and [C] can be obtained using ICE table

[A] + [B] <------> [C]

2 4 4 initlally after addition of B

-x -x +x change

2-x 4-x 4+x equilibrium

[4+x]/[4-x][2-x] = 2

4-x = 16 + 2x2 - 12x

2x2 +12-11x = 0

x = 4 or 1.5

if we take 4 then reactant A will become negative as A-x will become 2-4 = -2

so we have to take 1.5

[A]= 2-1.5 =0.5

[B] = 4-1.5 = 2.5

[C] = 4+x = 5.5

this one is also incorrect

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.