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1. Using the thermochemical equations 2 C2 He (g) + 702(g)--> 4 CO2 (g) + 6 H2 O

ID: 548622 • Letter: 1

Question

1. Using the thermochemical equations 2 C2 He (g) + 702(g)--> 4 CO2 (g) + 6 H2 O (g) AH =-2599 kJ c. H2 (g) +1/202 (9)H2O (9) AH =-286 kJ Calculate 4H for 2. Given the thermochemical equations: a. H2 (9)+Br2 (g)2HBr (g) b. H2 (g) 2H (g) c. Br2 (g)2Br (g) H = 224 kJ Calculate the for: H (g) r (g)>HBr (g) Use the standard enthalpies of formation found in Appendix C1 to calculate H for each of the following reactions: a. 6 CO2 (g) + 6H20 (I) >Cs H120s (s) + 6 02 (9) 3. b. 2Fe203 (s) +3C (s) 4Fe (s)3 CO2 (g) 32

Explanation / Answer

1)

lets try to write the required equation in terms of a,b,c

required reaction = -1/2*reaction a + (1/2)*reaction b + 2*reaction c

so,

delta H = (-1/2)*delta H1 + (1/2)*delta H2 + 2*delta H3

= (-1/2)*(-1560) + (1/2)*(-2599)+2*(-286)

= 780 - 1299.5 - 5724

= - 6243.5 KJ

Answer: - 6243.5 KJ

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