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Resources s previous | 1 of 6 next rt A The followi ng five beakers, each contai

ID: 549101 • Letter: R

Question

Resources s previous | 1 of 6 next rt A The followi ng five beakers, each containing a solution of sodium chloride (NaCl, also known as table salt) were found on a lab shelf: Beaker Contents 1 200. mL of 1.50 M NaCl solution 2 100. mL of 3.00 M NaCl solution 3 150. mL of solution containing 22.5 g of NaCl 4 100. mL of solution containing 22.5 g of NaCl 300. mL of solution containing 0.450 mol NaCl 5 Arrange the solutions in order of decreasing concentration. Rank from most concentrated to least concentrated. To rank items as equivalent, overlap them. Hints Reset Hel 020 FM

Explanation / Answer

answer: first we see the concentration of each beaker

beaker 1) concentration on NaCl solution is 1.50 M its given , nd concentration remain same if we take part of solution

2) similary concentration of second beaker is 3.00 M

3) we have to calculate concentration by using formula

concentration ( molarity ) = (mass given/(molar mass of NaCl * volume in mL) ) *1000

molar mass of NaCl= 58.44

concentration = ( 22.5/ (58.44 * 150 ) ) *1000

concentration = 2.57M

4)

we have to calculate concentration by using formula

concentration ( molarity ) = (mass given/(molar mass of NaCl * volume in mL) ) *1000

molar mass of NaCl= 58.44

   concentration = ( 22.5/ (58.44 * 100 ) ) *1000

concentration = 3.85M

5)

we have to calculate concentration by using formula

concentration ( molarity ) = (moles of NaCl/ volume in mL) ) *1000

concentration = (0.450/300)*1000

= 1.5M

so order is beaker number 4 > 2 > 3 > 1 = 5

most least

concentraion of Nacl solution in beaker 1 and 5 is same

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