A 1.2 kg block of iron at 21 C is rapidly heated by a torch such that 18 kJ is t
ID: 550303 • Letter: A
Question
A 1.2 kg block of iron at 21 C is rapidly heated by a torch such that 18 kJ is transferred to it. What temperature would the block of iron reach assuming the complete transfer of heat and no loss to the surroundings? If the same amount of heat was quickly transferred to a 890 g pellet of copper at 35 C, what temperature would it reach before losing heat to the surroundings? qcs, Fe(s)cs, Cu(s)===mcsT0.450 J/gC0.385 J/gC Express the final temperatures of the iron and copper in C to two significant figures separated by a comma.
Explanation / Answer
heat supplied(q) = m*s*DT
q = 18*10^3 j
m = mass of iron = 1.2 kg = 1.2*10^3 g
s = specific heat of iron = 0.45 j/g.c
DT = x-21
18*10^3 = 1.2*10^3*0.45*(x-21)
x = final temperature of iron = 54 c
2) heat supplied(q) = m*s*DT
q = 18*10^3 j
m = mass of iron = 890 g
s = specific heat of Cu = 0.385 j/g.c
DT = x-35
18*10^3 = 890*0.385*(x-35)
x = final temperature of iron = 88 c
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.