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ID: 551848 • Letter: C
Question
Cengage C Owest cengac enow com lrrakeAssignment takeCova en Activity do? ocator=assgrnment takeg takeAssignmentSessionLocator-assignment-take Chaptor 14: EOC (K 1.3 × 10-5 ) and 55.0 mL of 0.700 If NaCsH,02 A buffer is made using 45.0 mL of 0.750 l/HC3H,02 change the pH of the original buffer solution by 7.5%? Volume = what volume of 0.10 M NaOH must be added to 1 pt Question 29 1pt 1 pt Question 31 0 pt 1 pt Question 33 1pt 1 pt 1 pt 1pt pt 1 pt 1 pt 1 pt 1 pt Question 42 0 pt 1 pt Question 28 mL Question 30 Submit Answer Try Another Version 10 Item attempts remalning Question 32 Question 34 Question 35 Question 36 Question 37 Question 38 Question 39 Question 40 Question 41 Question 43 Progress 22/61 items Due Nov 1 at 11:55 PM Screenshat saved I he screenshot was added to your OneDrivc. OneDrive 3:20 PM 11/12017 Type here to searchExplanation / Answer
pka = -log(1.3*10^-5) = 4.89
no of mol of HC3H5O2 = 45*0.75/1000 = 0.03375 mmol
no of mol of NaC3H5O2 = 55*0.7/1000 = 0.0385 mmol
pH = pka + log(NaC3H5O2/HC3H5O2)
= 4.89+log(0.0385/0.03375)
= 4.95
after addition of NAoH
pH = 4.95 + (4.95*7.5/100) = 5.32
pH = pka + log(NaC3H5O2+NaOH/HC3H5O2-NaOH)
5.32 = 4.95+log((0.0385+x)/(0.03375-x))
x= 0.0121 mol
volume of NaOH = n/M = 0.0121/0.1*1000 = 121 ml
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