Equilibrium Exercises Put answers on a separate sheet of paper The following que

Question

Equilibrium Exercises Put answers on a separate sheet of paper The following questions are based on the reaction 2N0(g) Cl2(g) + 2NOCI(g) K,-6.5 x 10‘ at 308 K 1. Write the equilibrium-constant expressions, K, and K 2. At equilibrium, Pho 0.35 atm and Pe2-0.10 atm. Calculate the equilibrium partial pressure o NOCI 3. Calculate the molar concentrations of each gas at equilibrium at the temperature indicated above using the ideal gas equation. 4. Using the values from part 3, calculate the value of 5. Using the formula, K, -K.(RT), calculate K, from the given value of Kp and see if your number agrees with the answer from part 4 6·The volume of the container was doubled for the mixture of gases without calculating, predict the direction of the shift (left, right or no change) in the equilibrium. Determine the value of Q, to see if your prediction is correct 7. Perform the same analysis as part 6 based on the scenario that the original volume of the container was decreased by a factor of two.

Explanation / Answer

First, let us define the equilibrium constant for any species:

The equilibrium constant will relate product and reactants distribution. It is similar to a ratio

The equilibrium is given by

rReactants -> pProducts

Keq = [products]^p / [reactants]^r

For a specific case:

aA + bB = cC + dD

Keq = [C]^c * [D]^d / ([A]^a * [B]^b)

Kp = P-NOCl^2 / (P-NO)^2*(P-Cl2))

for KC

Kc = [NOCl]^2 /([NO]^2[Cl2])

Q2

find Peq

Kp = P-NOCl^2 / (P-NO)^2*(P-Cl2))

6.5*10^4 = P-NOCl^2 / ((0.35^2)*(0.1))

P-NOCl^2 = (6.5*10^4) * ((0.35^2)*(0.1))

P-NOCl = 796.25^0.5 = 28.21 atm

Q3

Find molar concentration given

PV = nRT

n/V= M = p/(RT)

[NO] = (0.35)/(0.082*308) = 0.013858 M

[Cl2] =  (0.10)/(0.082*308) = 0.003959 M

Q5.

using

Kp = Kc*(RT)^dn

find KC

6.5*10^4 = Kc *(0.082*308)^(2-3)

Kc = (6.5*10^4 ) / ((0.082*308)^(2-3))

Kc = 1641640

Q6

if V increases, P decreases

P decrease favours the most mol formation, so this is reactants ,s this favours reactants

Q7

if V decreases, P increases

P increase favours the least mol formation, so this is product,s this favours products

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.