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Problem 9.44 Part A A 600.0 mL bottle of Listerine is of a 27 % (v/v) ethyl alco

ID: 552548 • Letter: P

Question

Problem 9.44 Part A A 600.0 mL bottle of Listerine is of a 27 % (v/v) ethyl alcohol What is the volume (in mL) of ethyl alcohol in the bottle? Express your answer to two significant figures and include the appropriate units 160 mL Submit My Answers Give Up Correct Part B If the density of ethyl alcohol is 0.789 g/mL and the molar mass is 46.07 g/mol, calculate the molarity of ethyl alcohol in Listerine Express your answer to two significant figures and include the appropriate units Submit My Answers Give Up Incorrect Try Again; 3 attempts remaining Provide Feedback Contir

Explanation / Answer

Molarity = mol of ethyl alcohol / Volume of solution

V = 600 mL = 0.6 L

volume of ethanol = 27/100*600 = 162 mL

then

Mass = D*V = 0.789 g/mL * 162 mL = 127.818 g of ethanol

mol = mass/MW = 127.818/46

mol of ethanol = 2.7786

[ethanol] = mol/V= 2.7786/0.6 = 4.631 M

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