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ID: 552917 • Letter: I

Question

is owLv2 | Online teaching × e chegg Study I Guided s x C cvg.cengagenow.com/ilrn/takeAssignment/takeCovalent Activity do?locator-assignment-take&takeAssignmentSessionLocator-assignment-take; : Apps : kober portal D 2004 Saturn L300 H: web chemucsbedu -Baltimore Classificat Acute Viral Hepatitis Hepatitis A Treatme Jaundice: MedlinePl Other bookmarks Time Remaining: 1:44:06 UNIT TEST Use the References to access important values if needed for this question. Question 10 Question 11 Question 12 Question 13 Question 14 Question 15 Question 16 Question 17 Question 18 Question 19 Question 20 Question 21 Question 22 Question 23 Question 24 Question 25 Progress: 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt A scientist measures the standard enthalpy change for the following reaction to be -918.3 k.J Fe.Oj(s) + Als>A203(s) +2 Fe(s) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of Al203(s) is kJ/mol. Submit Answer Try Another Version 1 item attempt remaining 0/25 items Due Nov 2 at Next 11:00 PM Previous 8:39 PM 11/2/2017

Explanation / Answer

Fe2O3(s) + 2Al(s) ------------> Al2O3 (s) + 2 Fe(s)

delta H = -918.8 kJ

The enthalpy of formation of elements = 0

enthalpy of formation of Fe2O3 = -824.2 kJ/mol

the enthalpy of reaction = sum of enthalpies of formation of products - sum of enthlapiesof formation of reactants

-918.8 kJ = [ delta Hf (AL2O3) + 0] - [-824.2 +0]

thus delta Hf of AL2O3 = -918.8 -824.2

= -1743 kJ/mol