(a) mass, in grams, of 1.50 × 10 mol Cas (b) number of moles of NH4Cl in 86.6 g
ID: 554097 • Letter: #
Question
(a) mass, in grams, of 1.50 × 10 mol Cas (b) number of moles of NH4Cl in 86.6 g of this substance (c) number of molecules in 8.447 x 10 2 mol C&Hb; (d) number of O atoms in 6.25 × 10-3 mol Al(NOJ3 3.37 (a) What is the mass, in grams, of 2.50 × 10-3 mol of ammonium phosphate? (b) How many moles of chloride ions are in 0.2550 g of (c) what is the mass, in grams, of 7.70 × 1020 molecules of (d) What is the molar mass of cholesterol if 0.00105 mol has aluminum chloride? caffeine, CsH10N402 a mass of 0.406 g? sulfate? ammonium carbonate? aspirin, CoH,04? 3.38 (a) What is the mass, in grams, of 1.223 mol of iron(II) tb) How many moles ammonlum tons are in 6.955 g of (c) what is the mass, in grams, of 1.50 × 1021 molecules of d) What is the n ofExplanation / Answer
No of moles of Oxygen atoms present in one of Al(NO3)3 = 9 moles of Oxygen atoms present.
So that 6.25 x 10-3 moles of Al(NO3)3 contains how many moles Oxygen atoms present =?
= 6.25 x 10-3 x 9
= 56.25 x 10-3
= 5.625 x 10-2 moles of Oxygen atoms present
= 0.05625 moles of Oxygen atoms present.
One mole of Oxygen atoms contains 6.022 x 1023 molecules present.
So that in 5.625 x 10-2 moles of Oxygen contains how many number of Oxygen atoms present =?
= 6.022 x 1023 x 5.625 x10-2
= 33.874 x 1021 atoms
= 3.387 x 1022 atoms present.
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