Need help on 1 b ne Caieulator, and resource a. Bastcally, anything goes except

Question

Need help on 1 b

ne Caieulator, and resource a. Bastcally, anything goes except direct collaboration with classmates. For ungraded problems: all the above, as well as your classmates. Working together is encouraged for ungraded problems, Take care, though, that you actually understand ungraded problems if you are working in a group, and aren't just nodding along with your classmates. t Value: 20 pts raded Problems: 5.11, 5.19, 5.27,5.41,5.71, 5.85 (5 pts) led Problems: Xylose, a sugar, has a formula of CH O% In acrobic metabolism, it undergoes a reaction that is effectively equivalent to combustion (forming Co, and H:O by reaction with oxygen). Write a balanced equation for the combustion of xylose. (2 pts) CgM120,7.locat bH20 a. A coffee-cup calorimeter consisting of 100 of water is used to measure for this reaction. The combustion of 0.23 g of xylose raises the calorimeter temperature from 13.30 C to 21.86 C. What is 1? Note that it is not sufficient to Just find q! (3 pts) Qul (100.23 4.184 1g c) (sSu)

Explanation / Answer

b)

We have to calculate the mass of water formed from the balaced equation.

C6H12O6 + 6 O2 ----------------> 6 CO2 + 6 H2O

1 mol                                                     6 mol

180 g                                                     6 x 18 g = 108 g

0.23 g                                                      ?

Then,

                       ? = (0.23 g / 180 g) x 108 g H2O

                         = 0.138 g H2O

Hence,

Hrxn = q = m c dT

m= mass of water formed = 0.138 g

c = specific heat capacity of water = 4.184 J/g*celcius

Then,

Hrxn = q = m c dT = 0.138 g x  4.184 J/g*celcius x (21.86-13.3) oC = 4.94 J

Therefore,

Hrxn = 4.94 J

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