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need help thanks QUESTION1 1.25 polr Substances A B, and C can all act as oxidiz

ID: 554805 • Letter: N

Question

need help thanks

QUESTION1 1.25 polr Substances A B, and C can all act as oxidizing agents. In solution, A is green, B is yellow, and Cis red. In ns in which they participate, they are reduced to A,B,and C ions, all of which are colorless. When a solution of C is mixed with one containing 8B ions, the color changes from red to yellow. When a solution of C is mixed with one containing A-ions, the color remains red. Which activity series places the half reactions in order of decreasing reduction potential?

Explanation / Answer

Ans. Reduction potential of a chemical species is its ability to accept electrons from another chemical species.

Greater is the reduction potential, higher would be the ability to accept electrons, i.e. the chemical species can draw/accept electrons more easily.

# Given,

            A = Green      ; B = Yellow               ; C = Red        ; all anions are colorless

I. C (red) + B- -------------> B(Yellow) + C-         - Rxn 1

Since C accepts electron from B-, the reduction potential of C is higher than B-.

            Reduction potential C > B-             - statement 1

II. C (red) + A- ------------> No reaction

Since C can’t accepts electron from A-, the reduction potential of C is lower than A-.

            Reduction potential A- > C             - statement 1

# Comparing statement 1 and 2-

            Increasing Order of reduction potential: B- < C < A-

Since A has highest reduction potential, it will be the first chemical species to accept electron (here, from C-).

At second place, C would accept electron from B- because C has higher reduction potential than B but less than A.

# Greater is the reduction potential of a chemical species, better would it be an oxidizing agent because it can easily accept electrons from another molecule and oxidize it.

# Decreasing Order of reduction potential: A- > C > B-

That is, A would be reduced first because it can accept/draw electron with highest affinity.

C would be after A, but before B.

# So, correct option is. F

            A + e- ---> A-            - A is first to receive electrons (highest reduction potential)

C + e- ---> C-            - C is second to receive electron (intermediate reduction potential)

            B + e- ---> B-             - B is the last to receive electron (lowest reduction potential)