1) Silver nitrate reacts with barium chloride to form silver chloride and barium
ID: 554809 • Letter: 1
Question
1) Silver nitrate reacts with barium chloride to form silver chloride and barium nitrate a) Write and balance the chemical equation for this reaction b) If 7.5 moles of barium nitrate are formed at the end of this reaction, determine how many moles of silver nitrate you started with 2) Name the following compounds a) N Os b) BrF c) FE(OH)s d) Cr(OH3)s e) As2Os 3) There is a direct relationship between the volume of a gas and the temperature of a gas. Meaning that as temperature increases, the volume of the gas also increases. Use the behavior of the gases and its properites (pressure, volume, temperature, and moles of gas) to explain the relationship between temperature and volume in gases. 4) Phosphoric acid and sodium hydroxide react according to the balance equation shown below: a) H3PO, +3 NaOH Na POs +3H20 b) If 56.4 H3PO, reacts with 111 g of NaOH, how many grams of Na POs are produced? 5) What is an ideal gas? 6) A gas occupies 1900.0 ml at temperature of 47.0 C degrees. What is the volume at 132.0 C degrees?Explanation / Answer
1.a. 2AgNO3(aq) + BaCl2(aq) -------------> 2AgCl(s) + Ba(NO3)2(aq)
1 mole of Ba(NO3)2 produced from 2 moles of AgNo3
7.5 moles of Ba(NO3)2 produced from = 2*7.5/1 = 15 moles of AgNo3
2. a.N2O5 nitrogen pentoxide
b.BrF bromine fluoride
c. Fe(OH)3 iron(III) hydroxide
d. Cr(OH)3 chromium(III) hydroxide
e. As2O5 diarsine pentoxide
3.volume is directely proportional to temperature.
temperature is increases volume of the gas is increases.
4. a. H3Po4 + 3NaOH ------------> Na3PO4 + 3H2O
b. no of moles of H3PO4 = 56.4/98 = 0.575 moles
no of moles of NaOH = 111/40 = 2.775 moles
3 moles of NaOH react with 1 moles of H3Po4
2.775 moles of NaOH react with = 1*2.775/3 = 0.925 moles of H3PO4 is required.
H3Po4 is limiting reactant
1 mole of H3Po4 react with NaOH to gives1 mole of Na3Po4
98g of H3Po4 react with NaOH to gives 164g of Na3Po4
56.4g of H3Po4 react with NaOH to gives = 164*56.4/98 = 94.4g of Na3Po4
5. A gas fllows three gases law( Boy;s law,Charles law, Avogadro's law) is
called ideal gas.
6. initial final
V1 = 1900ml V2 =
T1 = 47+273 = 320K T2 = 132+273 = 405K
V1/T1 = V2/T2
V2 = V1T2/T1
= 1900*405/320 = 2404.7ml
7.Cr^+ is oxidized, Sn^+4 is reduced
Br^- is oxidized , Cl2 is reduced
Cu is oxidized , N is reduced.
8. AgNO3(aq) + KCl(aq) ------------> AgCl(s) + KNO3(aq)
Ag^+ (aq) +NO3^-(aq) + K^+ (aq)+Cl^-(aq) ------------> AgCl(s) + K^+ (aq) +NO3^-(aq)
Ag^+ (aq)+Cl^-(aq) ------------> AgCl(s)
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